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-2y^2+29y-64=0
a = -2; b = 29; c = -64;
Δ = b2-4ac
Δ = 292-4·(-2)·(-64)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{329}}{2*-2}=\frac{-29-\sqrt{329}}{-4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{329}}{2*-2}=\frac{-29+\sqrt{329}}{-4} $
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